Abstract
This work deals with a boundary value problem for a nonlinear multi-point fractional differential equation on the infinite interval. By constructing the proper function spaces and the norm, we overcome the difficulty following from the noncompactness of \([0, \infty)\). By using the Schauder fixed point theorem, we show the existence of one solution with suitable growth conditions imposed on the nonlinear term.
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1 Introduction
In this paper, we consider the existence of solution of boundary value problem for a nonlinear multi-point fractional differential equation,
where \(2<\alpha\leq3\) is a real number, \(f\in C(J\times R\times R, R)\) and \(\Gamma(\alpha)- \sum^{m-2}_{i=1}\beta_{i}\xi_{i}^{\alpha -1}\neq0\).
Due to the intensive development of the theory of fractional calculus itself as well as its applications, such as in the fields of physics, chemistry, aerodynamics, polymer rheology, etc., many papers and books on fractional calculus, fractional differential equations have appeared (see [1–16]).
For example, Bai [11] established the existence results of positive solutions for the problem
In [13], the authors considered the three-point boundary value problem of a coupled system of the nonlinear fractional differential equation
under the conditions \(0<\gamma\eta^{\alpha-1}<1\), \(0<\gamma\eta ^{\beta -1}<1\). By using the Schauder fixed point theorem, they obtained at least one solution of this problem.
The theory of boundary value problems on infinite intervals arises naturally and has many applications; see [17]. The existence and multiplicity of solutions to boundary value problems of fractional differential equations on the infinite interval have been investigated in recent years [18–21].
Agarwal et al. [22] established existence results of solutions for a class of boundary value problems involving the Riemann-Liouville fractional derivative on the half line by using the nonlinear alternative of Leray-Schauder type combined with the diagonalization process.
Arara et al. [23] considered boundary value problems involving the Caputo fractional derivative on the half line,
By using fixed point theorem combined with the diagonalization process, they obtained the existence of solutions.
Liang and Zhang [24] consider the m-point boundary value problem of fractional differential equation on the infinite interval
where \(2<\alpha\leq3\), \(D^{\alpha}_{0+}\) is the standard Riemann-Liouville derivative. Using a fixed point theorem for operators on a cone, sufficient conditions for the existence of multiple positive solutions were established. We point out that the nonlinear term of the equation does not depend on the lower order derivative of the unknown function.
In this paper, by constructing the proper function spaces and the norm to overcome the difficulty of the noncompactness of \([0, \infty)\) and using the Schauder fixed point theorem, we show the existence of one solution with suitable growth conditions imposed on the nonlinear term. Our method is different from [22, 23] in essence.
2 Preliminaries and lemmas
For convenience of the reader, we present the necessary definitions from fractional calculus theory [1].
Definition 2.1
The Riemann-Liouville fractional integral of order \(\alpha>0\) of a function \(u(t):R\rightarrow R\) is given by
provided the right side is point-wise defined on \((0, \infty)\).
Definition 2.2
The fractional derivative of order \(\alpha>0\) of a continuous function \(u(t):R\rightarrow R\) is given by
where \(n=[\alpha]+1\), provided that the right side is point-wise defined on \((0, \infty)\).
Lemma 2.1
Assume that \(u\in C(0,1)\cup L(0,1)\), and \(D^{\alpha }_{0+}\in C(0,1)\cup L(0,1)\). Then
for some \(C_{i}\in R\), \(i=1, 2, \ldots, N\), where N is the smallest integer greater than or equal to α.
Lemma 2.2
Given \(y(t)\in L[0, \infty)\). The problem
is equivalent to
Proof
By Lemma 2.1, we have
The boundary condition \(u(0)=u'(0)=0\) implies that \(c_{2}=c_{3}=0\).
Considering the boundary condition \(D^{\alpha-1}u(+\infty)= \sum^{m-2}_{i=1}\beta_{i}u(\xi_{i})\), we have
The proof is completed. □
Define the function spaces
with the norm
and
with the norm
Lemma 2.3
\((X, \|\cdot\|_{X})\) is a Banach space.
Proof
Let \(\{u_{n}\}_{n=1}^{\infty}\) be a Cauchy sequence in the space \((X, \|\cdot\|_{X})\), then \(\forall\varepsilon>0\), \(\exists N>0\) such that
for any \(t\in J\) and \(n, m>N\). Thus, \(\{u_{n}\}_{n=1}^{\infty}\) converges uniformly to a function \(\frac{v(t)}{1+t^{\alpha-1}}\) and we can verify easily that \(v(t)\in X\). Then \((X, \|\cdot\|_{X})\) is a Banach space. □
Lemma 2.4
\((Y, \|\cdot\|_{Y})\) is a Banach space.
Proof
Let \(\{u_{n}\}_{n=1}^{\infty}\) be a Cauchy sequence in the space \((Y, \|\cdot\|_{Y})\), then \(\{u_{n}\}_{n=1}^{\infty}\) is also a Cauchy sequence in \((X, \|\cdot\|_{X})\). Thus there exists a function \(v(t)\in X\) such that
Moreover,
and
It is easy to check that \(v=u'(t)\). Next we need to ensure that \(w=D^{\alpha-1}u(t)\).
In view of the Lebesgue dominated convergence theorem and the uniform convergence of \(\{D^{\alpha-1}u_{n}(t)\}^{\infty}_{n=1}\), there exists a positive constant \(M>0\) such that \(\frac{|u_{n}(t)|}{1+t^{\alpha-1}}\leq M\), \(n=1,2,\ldots\) . Then
together with
ensures that \(w=D^{\alpha-1}u(t)\).
Thus \((Y \|\cdot\|_{Y})\) is a Banach space. □
Because the Arzela-Ascoli theorem fails to work in Y, we need a modified compactness criterion to prove the compactness of the operator.
Lemma 2.5
Let \(Z\subseteq Y\) be a bounded set and the following conditions hold:
-
(i)
for any \(u(t)\in Z\), \(\frac{u(t)}{1+t^{\alpha-1}}\), \(\frac {u'(t)}{1+t^{\alpha-2}}\) and \(D^{\alpha-1}u(t)\) are equicontinuous on any compact interval of J;
-
(ii)
given \(\varepsilon>0\), there exists a constant \(T=T(\varepsilon )>0\) such that
$$\begin{aligned}& \biggl|\frac{u(t_{1})}{1+t_{1}^{\alpha-1}}-\frac {u(t_{2})}{1+t_{2}^{\alpha-1}} \biggr|< \varepsilon,\qquad \biggl|\frac{u'(t_{1})}{1+t_{1}^{\alpha-2}}- \frac {u'(t_{2})}{1+t_{2}^{\alpha-2}} \biggr|< \varepsilon,\quad\textit{and} \\& \bigl|D^{\alpha-1}u(t_{1})-D^{\alpha-1}u(t_{2}) \bigr|< \varepsilon \end{aligned}$$for any \(t_{1}, t_{2}>T\) and \(u(t)\in Z\). Then Z is relatively compact in Y.
Proof
We need to prove that Z is totally bounded. First we consider the case \(t\in[0, T]\). Define
It is easy to check that \(Z_{[0, T]}\) with the norm \(\|u\|_{\infty }= \sup_{t\in[0, T]} |\frac{u(t)}{1+t^{\alpha-1}} |\) is a Banach space. Then condition (i) combined with the Arzela-Ascoli theorem indicates that \(Z_{[0, T]}\) is relatively compact. Thus for any positive number ε, there exist finitely many balls \(B_{\varepsilon}(u_{i})\) such that
where
Similarly, the space
with the norm \(\|u'\|= | \frac{u'(t)}{1+t^{\alpha-2}} |\) and
with the norm
are Banach spaces. Then
where
Next we define
Now we take \(u_{ijp}\in Z_{ijp}\). Then Z can be covered by the balls \(B_{5\varepsilon}(u_{ijp})\), \(i=1,2,\ldots,n\), \(j=1,2,\ldots ,m\), \(p=1,2,\ldots,k\), where
In fact, for \(t\in[0, T]\),
and
For \(t\in[T, +\infty]\), we have
and
These ensure that
□
3 Main results
Define the operator T by
Theorem 3.1
Assume that \(f: J\times R\times R\rightarrow R\) is continuous. Then problem (1.1)-(1.2) has at least one solution under the assumption that
-
(H)
there exist nonnegative functions \(a(t)(1+t^{\alpha-1}), b(t), c(t)\in L^{1}(J)\), such that
$$\bigl\| f(t,x,y)\bigr\| \leq a(t)|x|+b(t)|y|+c(t), $$where \(\int^{\infty}_{0}c(t)\,dt<+\infty\).
Proof
First of all, in view of
together with the continuity of f, we see that \(T'u(t)\) and \(D^{\alpha -1}Tu(t)\) are continuous on J.
In the following we divide the proof into several steps.
Step 1 Choose the positive number
where
and \(\Lambda=\Gamma(\alpha)- \sum^{m-2}_{i=1}\beta_{i}\xi _{i}^{\alpha -1}\).
Let set
Then, \(A:U\rightarrow U\). In fact, for any \(u(t)\in U\), we have
Hence, \(\|Tu(t)\|_{Y}\leq R\), which shows that \(A:U\rightarrow U\).
Step 2 Let V be a nonempty subset of U. We will show that TV is relative compact. Let \(I\subset J\) be a compact interval, \(t_{1}, t_{2}\in I\) and \(t_{1}< t_{2}\). Then for any \(u(t)\in V\), we have
and
Note that for any \(u(t)\in V\), we have \(f(t, u(t), D^{\alpha-1}u(t))\) is bounded on I. Then it is easy to see that \(\frac{|Tu(t)|}{1+t^{\alpha-1}}\), \(\frac{|T'u(t)|}{1+t^{\alpha-2}}\), and \(D^{\alpha-1}Tu(t)\) are equicontinuous on I.
Considering the condition H, for given \(\varepsilon>0\), there exists a constant \(L>0\) such that
On the other hand, since \(\lim_{t\rightarrow+\infty}\frac {t^{\alpha -1}}{1+t^{\alpha-1}}=1\), there exists a constant \(T_{1}>0\) such that \(t_{1}, t_{2}\geq T_{1}\),
Similarly, in view of \(\lim_{t\rightarrow+\infty}\frac {(t-L)^{\alpha-1}}{1+t^{\alpha-1}}=1\), there exists a constant \(T_{2}>L>0\) such that \(t_{1}, t_{2}\geq T_{2}\) and \(0\leq s\leq L\),
In view of \(\lim_{t\rightarrow+\infty}\frac{(t-L)^{\alpha -2}}{1+t^{\alpha-2}}=1\), there exists a constant \(T_{3}>L>0\) such that \(t_{1}, t_{2}\geq T_{3}\), and \(0\leq s\leq L\),
Now choose \(T>\max\{T_{1}, T_{2}, T_{3}\}\). Then for \(t_{1}, t_{2}\geq T\), we have
and
Consequently, Lemma 2.5 shows that TV is relative compact.
Step 3 \(T:U\rightarrow U\) is a continuous operator.
Let \(u_{n}, u\in U\), \(n=1,2,\ldots\) , and \(\|u_{n}-u\| _{Y}\rightarrow0\) as \(n\rightarrow\infty\). Then, we have
Then the operator T is continuous in view of the Lebesgue dominated convergence theorem. Thus by Schauder’s fixed point theorem we conclude that the problem (1.1)-(1.2) has at least one solution in U and the proof is completed. □
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Acknowledgements
The work is sponsored by the NSFC (11201109), Anhui Provincial Natural Science Foundation (1408085QA07), the Higher School Natural Science Project of Anhui Province (KJ2014A200), and the outstanding talents plan of Anhui High school.
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Shen, C., Zhou, H. & Yang, L. On the existence of solution to a boundary value problem of fractional differential equation on the infinite interval. Bound Value Probl 2015, 241 (2015). https://doi.org/10.1186/s13661-015-0509-z
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DOI: https://doi.org/10.1186/s13661-015-0509-z